The series limit for the Balmer series of hydrogen spectrum occurs
at 3664 A. Calculate Ionization energy of hydrogen atom.
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Answer:
Given series is Blamer series,i.e.,
λ=3664A
o
and thus, n
1
=2;n
2
=∞
(a)∵E photon of series limit =ΔE=E
infty
−E
2
=−E
2
=
λ
hc
=
3664×10
−10
6.626×10
−34
×3×10
8
or E
2
=−5.42×10
−19
J
(b)∵E
1
=E
2
×n
2
=−4×5.42×10
−19
J
=−21.68×10
−19
J
Now for removal of electron from I orbit
λ
hc
=21.68×10
−19
;
21.68×10
−19
=
λ
6.626×10
−34
×3×10
8
∴λ=916
A
˚
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