Question

The series limit values are 8208A and 22800 A for the quantum numbers n1 and n2 in the atomic
spectrum of the hydrogen. What is the wavelength for the radiation emitted for the transition n2 to n1
in A?
(A) 15282
(B) 12258 (C) 12825 (D) 15822
​

Answer 1

Answer:

The correct answer will be option A ,15282

Explanation:

The series limit values are 8208 A and 22800 A for the quantum numbers n1 and n2 in the atomic  spectrum of the hydrogen.

Therefore,

n1 = 8208/912

   =9

   =3^2  

Hence, n1=3

n2 = 22800/912

      =25

      =5^2    

Hence n2=5

we know that

1/λ=R[1/n1^2−1/n2^2] [ where λ is the wavelength]

putting the value of n1 and n2

=> 1/λ=1.09×10^7 (1/3^2−1/5^2)          

         =1.09×10^7× (25−9/225)          

          =1.09×107× (16/225)

=>  λ=225/16×1.09×10^7    

         =15.282×10^7 m        

          =15282 A