Question

the set of all positive roots of the equation (x-1)(x+1)(x^2-1)=0

Answer 1

use the property of x^2 - y^2

Answer 2

Answer:

x=1

Step-by-step explanation:

We have been given the equation

$(x-1)(x+1)(x^2-1)=0$

From the zero product property, we have

$x-1=0,x+1=0,x^2-1=0\\\\x=1,-1,x^2=1\\\\x=-1,1,-1,1$

Hence, the positive root is x =1