Math, asked by parvathypt, 9 days ago

The set of all real value's of satisfy |x^ 2 -5|x|-4|>=|2x^ 2 -3|x|+1||
(A) (- 3, 2);
(C)[- 3, 6]
(B) [2, 3)
(D) [- 3, 3]​

Answers

Answered by mdashifiqbalsardar
0

Given,

8

5x−4

5

x−3

=

4

x+6

LCM of 8,5,4 is 40.

⇒5(5x−4)−8(x−3)=10(x+6)

⇒25x−20−8x+24=10x+60

⇒25x−8x−10x=60−24+20

⇒7x=56

⇒x=8

Was this answer helpful?

Similar questions