Question

The set of first four terms of the Arithmetic progression 3n-2​

Answer 1

Solution:

» tn = 3n - 2 ... given

» t1 = 3 (1) - 2 = 1

» t2 = 3 (2) - 2 = 4

» t3 = 3 (3) - 2 = 7

» t4 = 3 (4) - 2 = 10

Therefore, (1, 4, 7, 10) is set of first four terms of the A.P.

Answer 2

Answer:

Tn = 3n -2

So,

T1 = 3*1 -2 = 3 -2 = 1

T2 = 3*2 -2 = 6 -2 = 4

T3 = 3*3 -2 = 9 -2 = 7

T4 = 3*4 -2 = 12 -2 = 10

so,

the first 4 terms are , 1,4,7,10