Question

the set of first four terms of the arithmetic progression 3n -2
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Answer 1

taking n = 1

= 3(1)-2

= 1

taking n= 2

= 3(2)-2

= 4

taking n = 3

= 3(3)-2

= 7

taking n = 4

= 3(4)-2

= 10

therefore, the AP is 1,4,7,10..

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