Question

The set of solutions of the quadratic equation x^2+5x+6=0​

Answer 1

Answer:

x = -3 or x = -2

Step-by-step explanation:

x²+5x+6 = 0

=> x²+2x+3x+6 = 0

=> x(x+2)+3(x+2) = 0

=> (x+3)(x+2) = 0

=> x = -3 or x = -2

Answer 2

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x² + 5x + 6 = 0

Now, doing middle term factorisation

⟼ x² + ( 3 + 2 )x + 6 = 0

⟼ x² + 3x + 2x + 6 = 0

⟼ x ( x + 3 ) + 2 ( x + 3 ) = 0

⟼ ( x + 3 ) ( x + 2 ) = 0

Therefore , the values of x are -

Either

⟼ ( x + 3 ) = 0

⟼ x = -3

Or

⟼ ( x + 2) = 0

⟼ x = -2