Question

The set of values of a, if origin lies in the bisector of acute angle of the lines ax +2y-3-0 and
x+y+7= 0 is
(1) a<-2
(2) a>-2
(3) a > 2
(4) a 2​

Answer 1

Answer:

2) a>-2 is correct answer.

Hope this answer is helpful

Answer 2

 SincAnswer:

Step-by-step explanation:

The equations are

ax+2y-3=0 and x+y+7=0

Therefore the required angle bisector will be

$ax+2y-3/\sqrt{x} ^{2}+2^{2}$= $x+y+7/\sqrt{x} ^{2} +y^{2}$  

e, (a)(1)+(2)(1)=a+2<0=a<-2

Therefore, positive will yield the equation of acute angle bisect