The set of values of p for which the roots of the equation
3x {}^{2} + 2x + (p - 1)p = 03x
2
+2x+(p−1)p=0
are of opposite sign is _______?
FIND value of p
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Answer:
Step-by-step explanation:
Let one root is α. So, second root will be −α.
∴ Sum of roots =α−α=0
∴ Product of roots =−α2
It means product of rootsis less than 0.
Product of roots in the given equation is p(p−1)3.
∴p(p−1)3<0
⇒(p(p−1))<0
∴p∈]0,1[
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