The set of values of 'x' satisfying (x²-x-1)(x²-x-7)<-5 is (a,b)U(c,d) then a+b+c+d is equal to
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(x
2
−x−1)(x
2
−x−7)<−5
Let x
2
−x be t
(t−1)(t−7)<−5
t
2
−8t+7+5<0
t
2
−8t+12<0
(t−6)(t−2)<0
(x
2
−x−6)(x
2
−x−2)<0
(x−3)(x+2)(x−2)(x+1)<0
x∈(−2,−1)∪(2,3)
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