Math, asked by Sonamgupta958008, 5 months ago

The set of vectors (5,3,4), (1,2,5),(1,1,2)........... a basis of a vector space R3
(a) forms
(b) does not form
(c) may or may not
(d) none ​

Answers

Answered by autkarsh376
0

Answer:

total gaz the highlighted words you have received this communication in ey

Answered by AlluringNightingale
1

Answer :

b) does not form

Reason :

The given vectors are not linearly independent .

Explanation :

Please refer to the attachments .

Some important information :

Vector space :

(V , +) be an algebraic structure and (F , + , •) be a field , then V is called a vector space over the field F if the following conditions hold :

  1. (V , +) is an abelian group .
  2. ku ∈ V ∀ u ∈ V and k ∈ F
  3. k(u + v) = ku + kv ∀ u , v ∈ V and k ∈ F .
  4. (a + b)u = au + bu ∀ u ∈ V and a , b ∈ F .
  5. (ab)u = a(bu) ∀ u ∈ V and a , b ∈ F .
  6. 1u = u ∀ u ∈ V where 1 ∈ F is the unity .

♦ Elements of V are called vectors and the lements of F are called scalars .

♦ If V is a vector space over the field F then it is denoted by V(F) .

Linear combination :

A vector v in a vector space V is called a linear combination of the vectors v₁ , v₂ , v₃ , . . . , vₖ if v can be expressed in the form :

v = c₁v₁ + c₂v₂ + c₃v₃ + . . . + cₖvₖ

where c₁ , c₂ , c₃ , . . . , cₖ are scalars and are called weights of linear combination .

Span / spanning set / generating set :

Let v₁ , v₂ , . . . , vₙ be the n vectors of a vector space V(F) , then the set of all linear combinations of v₁ , v₂ , . . . , vₙ , i.e. span{v₁ , v₂ , . . . , vₙ} = {c₁v₁ + c₂v₂ + . . . + cₙvₙ : cᵢ ∈ F}

♦ The spanning set is also called the subset of V spanned (or generated) by v₁ , v₂ , . . . , vₙ .

Linear dependence :

Let v₁ , v₂ , . . . , vₙ be the n non-zero vectors of a vector space V(F) . If for c₁v₁ + c₂v₂ + . . . + cₙvₙ = 0 (cᵢ ∈ F are scalars) , there exists atleast one cᵢ ≠ 0 , then v₁ , v₂ , . . . , vₙ are called linearly dependent .

♦ If the vectors v₁ , v₂ , . . . , vₙ are linearly dependent , then atleast one of these vectors can be expressed as a linear combination of the remaining vectors .

Linearly independence :

Let v₁ , v₂ , . . . , vₙ be the n non-zero vectors of a vector space V(F) . If for c₁v₁ + c₂v₂ + . . . + cₙvₙ = 0 (cᵢ ∈ F are scalars) , all cᵢ = 0 , then v₁ , v₂ , . . . , vₙ are called linearly independent .

♦ If the vectors v₁ , v₂ , . . . , vₙ are linearly dependent , then none of these vectors can be expressed as a linear combination of the remaining vectors .

Basis :

A set B of vectors in a vector space V(F) is called a basis of V if all the vectors of B are linearly independent and every vector of V can be expressed as a linear combination of vectors of B (i.e. B must spans V) .

Attachments:
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