Question

The set S = {1, 2, 3, ......., 12} is to be partitioned into three sets A, B, C of equal size. Thus A ∪ B ∪ C = S, A∩B = B∩C = A∩C = Ф. The number of ways to partition S is
$(a) \frac{12!}{(4!)^3} \\(b) \frac{12!}{(4!)^4} \\(c) \frac{12!}{3!(4!)^3}\\(d) \frac{12!}{3!(4!)^4}$

Answer 1

Answer:

Step-by-step explanation: