Question

The set {x | x = 3p-2, 1 < p < 5 and p ∈ N} is the same as

Answer 1

Step-by-step explanation:

A = {x | x = 3p –2, 1 < p < 5 and p E N}

=> x = 3p -2

p is a natural number between 1 and 5.

x = 3(2) -2

x = 4........(1st case)

x = 3(3) - 2

x = 7 ......(2nd case)

x = 3(4) - 2

x = 10......(3rd case)

Henceforth, any other case is not possible as according to the condition, 1 < p < 5.

Therefore,

A = { 4, 7, 10 } in roster form.