Question

The seven dgit number 345a65b is divisible by 9. Find the maximum possible value of a+b. a)4 b)22 c)13 d)15​

Answer 1

Answer:

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Answer 2

c is the correct option

when we add the number that divisible by 9 , we get the multiple of 9.

so 3+4+5+a+6+5+b = 23 +a+b

a+b can be 4 or 13

in the question they have asked the maximum value so 13 is the answer