Question

The seventh-grade class is building target areas for a PE activity. The bases for the game will be in a circular shape. The diameter of each circle is 3 feet. Approximately, how many square feet of the turf needs to be painted for a base circle? Use 3.14 for π and round your answer to the nearest tenth. (1 point)

7.1 square feet
9.4 square feet
18.8 square feet
28.3 square feet

Answer 1

Step-by-step explanation:

area of a circle= πr^2

given,

d=3 feet=3/2=1.5 feet

hence,

area of a circle= πr^2

= 3.14×(1.5)^2

= 7.065

=7.1 square feet.

Answer 2

Answer:

7.1ft of the turf needs to be painted for a base circle.

Step-by-step explanation:

Given that,

The seventh-grade class is building target areas for a PE activity in which bases for the game will be in a circular shape and The diameter of each circle is 3 feet.We are required to find the approximate area of the turf to be painted.It is equivalent to the area of the given circle.Therefore,Area of the circle is

$A=\frac{\pi}{4}d^{2}$

Substituting the value of diameter in the above relation,we get the area as

$A=\frac{3.14}{4} \times 3^{2} =7.065ft \approx 7.1ft$

Therefore,7.1ft of the turf needs to be painted for a base circle.

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