Question

the seventh term of a n arithmetic progression is 4times it,2and 12term is 2more than 3times of its 4th term . find the progression​

Answer 1

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Itz Me Kushi!

The 7th term of an arithmetic progression is four times its second term and twelfth term is 2 more than three times of its fourth term.Find progression.

7th Term = a + 6d

2nd term = a + d

7th term = 4 * (2nd Term)

=> a + 6d = 4 (a + d)

=> a + 6d = 4a + 4d

=> 2d = 3a   - eq 1

12th term = a + 11d

4th term = a + 3d

12th term = 2 + 3 * 4th term

a + 11d = 2 + 3 *(a + 3d)

=> a + 11d = 2 + 3a + 9d

=> 2d = 2a + 2   - eq2

Equating both equations

3a = 2a + 2

=> a = 2

2d =3a

=> 2d = 6

=> d= 3

AP = 2 + (n-1)3

= 2 + 3n - 3

= 3n - 1

2 , 5 , 8 , 11....

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