Question

The seventh term of an AP is 32 and it's 13th term is 62.find the AP.

Answer 1

hey mate,
it's given that
a7 = 32 and a13 = 62
then, a + 6d =32 --------------(1)
a + 12d = 62 --------------(2)
then eliminating (1) and(2)
6d = 30
d =30/6
d = 5.

substituting value of d in (1)
a + 6d = 32
a + 6(5) = 32
a = 32-30
a = 2

The AP will be 2,7,12,17......... so on

I hope this helps u!