English, asked by raghavpatel798, 9 months ago

The
sha
60) A 500 W electric heater is designed to work with a
115 V line. If the voltage of the line drops to 110, then
what will be the percentage loss of energy liberated?
Ans. 8.5%
Con
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Answers

Answered by DIWAKARrly
2

Answer:

Brainly.in

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Secondary School Physics 5 points

A 500W electric heater is designed to work with a 115V line.If the voltage of the line drops to110V,then what will be the percentage loss of energy liberated

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Answer:

8.5%

Explanation:

Given

A 500 W electric heater is designed to work with a 115 V line.If the voltage of the line drops to 110 V,then what will be the percentage loss of energy

Now power dissipated in external resistance will be

P = (E / R + r)^2 R

P1 = v1^2 / R = (115)^2 / R

P2 = v2^2 / R = (!10)^2 / R

Now change will be P1 – P2 / P1

= 115^2 – 110^2 / R / 115^2 / R

= (115 + 110)(115 – 110) / 115^2

= 1125 / 13,225

= 0.0850 x 100

= 8.5%

So percentage loss of energy liberated will be 8.5%

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