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60) A 500 W electric heater is designed to work with a
115 V line. If the voltage of the line drops to 110, then
what will be the percentage loss of energy liberated?
Ans. 8.5%
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Answer:
Brainly.in
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Secondary School Physics 5 points
A 500W electric heater is designed to work with a 115V line.If the voltage of the line drops to110V,then what will be the percentage loss of energy liberated
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Answer:
8.5%
Explanation:
Given
A 500 W electric heater is designed to work with a 115 V line.If the voltage of the line drops to 110 V,then what will be the percentage loss of energy
Now power dissipated in external resistance will be
P = (E / R + r)^2 R
P1 = v1^2 / R = (115)^2 / R
P2 = v2^2 / R = (!10)^2 / R
Now change will be P1 – P2 / P1
= 115^2 – 110^2 / R / 115^2 / R
= (115 + 110)(115 – 110) / 115^2
= 1125 / 13,225
= 0.0850 x 100
= 8.5%