Question

The shadow of 60m tree is 18m, then the height of the tree whose shadow is 24m at the same time of the day is​

Answer 1

Answer:

80 m

Step-by-step explanation:

given that the

length of tree is 60 m

and it's shadow is 18m

at the same time of the day

shadow is 24m then length of tree is x

18 m shadow ---> 60 m tree

1m shadow. --->60/18 m tree

24 m shadow --> (60/18)×24 m tree

x= (60/3)×4

x=20×4

x =80m

Answer 2

Given :- The shadow of 60m tree is 18m .

To Find :- The height of the tree whose shadow is 24m at the same time of the day ?

Concept used :- At same time angle of elevation of sun is equal .

Solution :-

In right angled ∆CAB,

→ CA = Height of tree = 60 m

→ AB = Shadow of tree = 18 m

→ ∠CBA = θ

So,

→ tan θ = CA/AB

→ tan θ = 60/18

→ tan θ = 10/3 ----------- Equation (1)

now, in right angled ∆RPQ,

→ RP = Let height of tree .

→ PQ = Shadow of tree = 24 m

→ ∠CBA = θ

So,

→ tan θ = RP/PQ

→ tan θ = RP/24

putting value of Equation (1) in LHS,

→ 10/3 = RP/24

→ 3•RP = 24 × 10

→ 3•RP = 3 × 8 × 10

dividing both sides by 3,

→ RP = 8 × 10

→ RP = 80 m .

Hence, the height of the tree is equal to 80 m .

Learn more :-

The diagram shows two planks are slanted on a vertical wall.

Express cot x in terms of p.

https://brainly.in/question/24608435