Question

The shadow of a 4m high pillar of 2√3m, then find the angle of elevation of sun​

Answer 1

Answer:

Let the angle of elevation be x.

Then tan x from horizontal will be (height of pillar/lenght of shadow)

Tan x =(4/2√3)

Tan x = (2/√3)

X= tan^-1(2/√3)

hope you understand this

Answer 2

The angle of elevation of sun​ is $66.586^{\circ}$

Step-by-step explanation:

Length of pillar = 4 m

Length of shadow =$2 \sqrt{3} m$

To find the angle of elevation :

$Tan \theta = \frac{Perpendicular}{Base}$

$Tan \theta = \frac{4}{\sqrt{3}}$

$\theta = tan^{-1}\frac{4}{\sqrt{3}}$

$\theta =66.586^{\circ}$

Hence  the angle of elevation of sun​ is $66.586^{\circ}$

#Learn more:

A pole 6m high casts a shadow 2√3m long on the ground, then find the angle of elevation of sun.

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