Question

The shadow of a building is 20 m long when the angle of elevation of the sun is 60o. Find the height of the building.

Answer 1

hope it helps...... bro

Answer 2

hi!

AB is the height of the building.

BC is its shadow.

BC = 20m.

The angle of elevation of the sun is 60°

<ACB = 60°

In triangle ABC,

$\tan(60) = \frac{ ab }{bc}$
$\sqrt{ 3} = \frac{ab}{20}$


$ab = 20 \times \sqrt{3}$

$ab \: = 20 \times 1.73$

$ab = 34.60m$


I.e
AB = 34.60m.

Therefore,
The height of the building is 34.60m.


hope this helps ! !