the shadow of a pole standing on a level ground is found to be 45m longer when the sun's altitude is 30° then when it was 60°.determine the height of the pole.[√3=1.73]
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tan30=h/x+45
√3h=x+45.....(1)
tan60=h/x
x=h/√3.....(2)
by using eq..(2)in(1)
√3h=h/√3+45
h=45√3/2
h=38.925
√3h=x+45.....(1)
tan60=h/x
x=h/√3.....(2)
by using eq..(2)in(1)
√3h=h/√3+45
h=45√3/2
h=38.925
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