the shadow of a pole with the height of 10 m is 6 m then find the height of another pole whose shadow is 9 m at the same time
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Answer:
We have,
Pole of height AB=10m
Shadow of length BC=12m
Same time
Pole of height AB=?
Shadow of length BC=15m
In ΔABC
tanθ=
BC
AB
=
12
10
…… (1)
InΔABC
tanθ=
BC
AB
=
15
AB
……. (2)
Angle is equal in same time,
By equation (1) and (2) to, we get
12
10
=
15
AB
AB=
12
10×15
AB=
4
10×5
AB=
2
25
=12.5m
Hence, this is the answer.
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