Question

The shadow of a tower becomes 60m longer when the angle of elevation of the the sun increase from 45° to 30° then the height of the tower is​

Answer 1

Answer:

h=height  

In△ABC

tan45∘=ABBC

11=ABBC=AB:BC=1:1.....(i)

In△ABD

tan30∘=ABBD

13–√=ABBD⇒AB:BD=1:3–√.....(ii)

Now,

CD=BD−BC

CD=3–√−1

3–√−1 units=60

H=1 unit=603–√−1

=603–√−1×3–√+13–√+1

h⇒30(3–√+1)m