the shadow of a tower on level ground increases in length by x metres when the altitude of the sun changes from 45 to 30. calculate the value of x, given that the height of the tower is 25 metres, correct to 3 significant places
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Answer:
18.301 meters
Step-by-step explanation:
Let ABC be the triangle where B is the right angle vertex and C is vertex forming an angle with the ground.
Let BD be the new length of the shadow formed.
Thus, CD = x
Also, given that AB = 25m
In ABC
∠ACB = 45°
Thus, tan(45) = AB/BC
ie. 1 = 25/BC (since tan(45) = 1)
Thus, BC = 25m
In ABD
∠ADB = 30°
tan(30) = AB/BD
1/√3 = 25/BD
∴ BD = 25√3
Change in length of shadow = BD - BC
25√3 - 25 = x
x = 25(√3-1)
∴ x = 18.301 metres
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