Question

The shadow of a tower standing on a level ground is 45 metres when sun altitude is 30 ° find the height of the tower.​

Answer 1

Step-by-step explanation:

$\tan(30) = \frac{ab}{bc} \\ \frac{1}{ \sqrt{3} } = \frac{ab}{45m} \\ \frac{45}{ \sqrt{3} } = ab \\ \frac{45 \sqrt{3} }{3} = ab \\ 15 \sqrt{3} m = ab$

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