Question

The shadow of a tower standing on a level ground is found to be 40 m longer. When the sun altitude is 60 degree. Find the height of the tower.

Answer 1

Answer:

Step-by-step explanation:

so

$tan60=\sqrt{3} =opposite/adjacent$

opposite is shadow and adjacent is height

$\sqrt{3} =\frac{40}{h}\\ h=\frac{40}{\sqrt{3} } m$