Question

the shadow of a tower standing on a level ground is found to be 40 m longer when the sun's altitude is 30 degree then when it is 60 degree. Find the height of the tower.

Answer 1

I hope u get the.answer
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Answer 2

Given:

The shadow of a tower is found to be 40m longer when sun’s altitude is 30° than when it is 60°

To find:

The height of the tower

Calculation:

From ΔABD

=> Tan(60°) = h/x

=> √3 = h/x

=> h = √3x               …(1)

From ΔABC

=> Tan(30°) = h/(40+x)

=> 1/√3 = h/(40+x)

=> h√3 = 40+x

=> 3x = x+40           [from eq(1)]

=> x = 20

Substitute the value of x in eq(1)

=> h = √3x

=> h = 20√3 m

The height of the tower is 20√3 m