Question

the shadow of a tower standing on a level ground is found to be 30 m longer when the sun's angle of elevation is 30°, than when it was 60°, find the height of the tower.

ರ╭╮ರ​

Answer 1

Answer:

15 m

Explanation:

Let:

AB be the tower = x

BC be the shadow at 60 degrees = y

BD be the shadow at 30 degrees

According to the question, CD = 30 m

Now, Tan ACB = tan 60 degrees = AB/ CB

==> y/x = $\sqrt{3}$

y = x$\sqrt{3}$

And Tan ADB = tan 30 degrees = AB/ BD

==> $\frac{y}{x+30}$ = 1/$\sqrt{3}$

==> $\frac{xroot3}{x+30}$= 1/$\sqrt{3}$

==> 3x = x + 30

==> 2x = 30

==> x = 15 m

Answer 2

hey can you tell me your all acc name's please..

don't want to tell me the name of the secret acc, I know you don't.. lol