Question

The shadow of a tower standing on a level plane is found to be 50m longer when sun altitude is 30 degree than when it is 60 degree find the height of tower

Answer 1

Answer:

APPLY TRIGONOMETRY

Answer 2

tan60=

BC

h

BC=

3

h

……….(1)

tan30

o

=

BC+50

h

⇒BC+50=

3

h

BC=

3

h−50 ……….(2)

From (1) & (2)

3

h

=

3

h−50

⇒h=3h−50

3

⇒2h=50

3

⇒h=25

3

.