Question

The shadow of a tower standing on a level plane is found to be 50m longer when sun's
elevation is 30° then when it is 60degree. Find the height of the tower.​

Answer 1

Answer:

The shadow of a tower standing on a level plane is found to be 50 m longer. When Sun's elevation 30^o than when it is 60^o . Find the height of tower.

Answer 2

Answer:

Let AB be tower. BC be original shadow.

BD be final shadow.

Given BD-BC = CD = 50m

∴ In AABC, tan 60° = AB/BC

= AB/√3 = BC ...(1)

In ∠ABD,

tan 30° = AB/BD

= 1/√3 = AB/(BC+CD)

= AB√3 = AB/√3+50 (From 1)

= AB√3-AB/√3 = 50

= 3AB-AB/√3 = 50

=> AB = 50√3/2 = 25√3 = 25*1.732

=> 43.30m