Question

the shadow of a tower standing on level ground is found to be 40 m longer when Sun's altitude is 30 degrees than when it was 60 degree find the height of the tower

Answer 1

Let the height of tower = h (m)
In ∆ABC,
tan 30° = 
 = 
 = 
√3h = 40 ---------------(1)
In ∆ABD,

tan 60° = 
√3 = 
h =√3  -------(2)
on substituting value of h from eqn. (2) in eqn. (1)
h = √3× (√3h-40)
h = 3h-40√3
2h = 40√3
h = 20√3 m.
Therefore height of tower is 20√3 m.

Answer 2

Hope it helps you!
The solution of this question is in the image.