Question

The shadow of a tower standing on the level ground is found to be 40 m longer when the sun’s altitude is 30 than when it is 60 Find the height of the tower.

Answer 1

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Answer 2

Let length of shadow be 'S' m when sun's altitude is 60.
Therefore, tan 60 = H/S,
where H= Height of Tower
=> 3^(1/2) = H/S
=> H = S × 3^(1/2)
Again, tan 30 = H/(S+40)
=> 1/3^(1/2) = S × 3^(1/2)/(S+40)
=> S = 20 m
Therefore, H = 20 × 3^(1/2) m
= 34.64 m