Question

The shadow of a tower when the angle of elevation of the sun is 45°, is found to be 10 m longer than when it was 60° . The height of the tower is

A) 5(√3 - 1) m B) 5(√3 + 1) m C) 10 (√3 - 1) m D) 10 (√3 + 1) m

Answer 1

Answer: Let length of shadow when it is 60 be x

Then x+10=shadow when 45

Tan60 =h/x

Root3x = h

Then root3x=10+x

Root 3x-x=10

X=10[root3+1]/2

H=5(root 3+1)× root3

H=23.66