Math, asked by riyasinghri, 1 year ago

The shadow of a tower, when the angle of elevation of the sun is 45° is found to be a 10 m long then when it is 60°. Find the height of the tower.

Answers

Answered by bunnysugar2003
3

Answer:

let AB be the tower with height h m

In ΔABC

tan 45°= \frac{AB}{BC}

1= \frac{h}{10+x}

h= 10+x -------(1)

In ΔABD

tan 60° = \frac{AB}{BD}

√3= \frac{h}{x}

h= x√3 --------(2)

from 1 and 2

10+x=x√3

x√3-x =10

x(√3-1) = 10

x(0.732) = 10

x= \frac{10}{0.732}

x= 13.66m

height of tower is 13.66m



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