Question

The shadow of a vertical pillar is a same the height of pillar then find angle of elevation.​

Answer 1

❥${\underline{\underline{\large{\mathtt{ANSWER:-}}}}}$

Angle of elevation is 45°.

❥${\underline{\underline{\large{\mathtt{EXPLANATION:-}}}}}$

•GIVEN :

• The shadow of a vertical pillar is a same the height of pillar.

•TO FIND :

• Angle of elevation.

• SOLUTION :

Let the height of the pillar be AB and the shadow of the pillar be BC.

Shadow of the pillar is the same height of pillar.

$\sf{Height\:of\:pillar=Shadow\:of\: pillar}$

$\implies\sf{AB=BC}$

Let the angle of elevation be $\angle\:ACB=\theta$

∆ABC is a right triangle.

In case of ∆ABC,

$\sf{\frac{AB}{BC}=tan\theta}$

$\implies\sf{\frac{BC}{BC}=tan\theta\:[We\:know\:AB=BC]}$

$\implies\sf{1=tan\theta}$

$\implies\sf{tan45=tan\theta\:[We\:know\: tan45=1]}$

$\implies\sf{45=\theta}$

Therefore, the angle of elevation is 45°.

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★MORE INFORMATION :

Some formulas related to trigonometry:-

• sin²∅ +cos²∅ = 1

• 1+tan²∅=sec²∅

• 1+cot²∅ = cosec²∅

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Answer 2

$\huge \mathfrak{Answer:-}$

$\implies$45 = (theta)

$\large\underline\mathrm{Given:-}$

• The shadow of a vertical pillar is a same the height of pillar.

$\large\underline\mathrm{To \: find}$

• Angle of elevation.

$\large\underline\mathrm{Solution}$

• Let the height of the pillar be AB and the shadow of the pillar be BC.
• Shadow of the pillar is the same height of pillar.

$\implies$ AB = BC

• Let the angle of elevation be ACB = (theta).

$\large\underline\mathrm{∆ABC \: is \: a \: right \: triangle.}$

$\large\underline\mathrm{In \; ∆ABC,}$

$\implies$AB/BC = tan(theta)

$\implies$BC/BC = tan(theta)

$\implies$1 = tan(theta)

$\implies$tan 45° = tan(theta)

$\implies$45 = (theta)

$\large\underline\mathrm{hence,}$

$\large\underline\mathrm{the \: angle \: of \: elevation \: is \: 45°.}$

$\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}$