Math, asked by sansjrj, 1 year ago

the shadow of a vertical tower on level ground increases by 10 m when the altitude of the sun Changes from 45° to 60°, find the height of the tower.

Answers

Answered by rameshkumarbhoi3

BC=x,CD=10m,BD=x+10m Tan45=AB/BD=>1=AB/x+10=>AB=x+10. tan 60=AB/BC=>root 3=x10/x. root 3x =x+10=>x=10/root3-1=>x=13.66 AB=x+10=23.66m(answer)

sansjrj: please can you draw and the send the rough figure?

rkdisha: it's wrong

rkdisha: answer

sansjrj: then wat's the correct answer?

rkdisha: its not coming wait I'll show you

sansjrj: ok thanks ;)

Answered by rkdisha

see it's coming in negative and I before taking only root 3 and not it's value then only it was not coming

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sansjrj: thanks again but distance can never be negative... right..So the answer would be 17.3 m?? right??

rkdisha: yes

rkdisha: but is the answer correct

sansjrj: hmm..okk

rameshkumarbhoi3: this answer is wrong please check it

rkdisha: ya we have to divide 17.3÷0.73

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