Question

The shadow of the tower standing on a flat ground is 40 m. Gets longer
While the altitude of the Sun decreases from 60 ° to 30 °. Tower height known
Please do. (Given 3 = 1-732)​

Answer 1

Answer:

Let height of tower be hm and distance AD be xm

In∆ABD,

tan60°=AB/AD

√3=h/x

h=√3x.........(i)

In∆ACB,

tan30°=AB/AC

1/√3=h/40+x

h√3=40+x

√3x.√3=40+x

3x=40+x

2x=40

x=20m

From eq.i we get

h=√3x

h=1.732×20

h=34.64m

Height of tower is 34.64m.