Question

The shadows of 1om high pole is 6m then find shadow of 15m high pole on same day same time

Answer 1

• they are in direct variation
• so,y/x=k
• 10/6=k
• 15/y=k, where k is equal to constant of variation
• 15/y=10/6
• 10y=15*6
• y=90/10
• y=9
• therefore shadow of 50m pole is equal to 9 metre