Question

The shape of a capsule is rectangular in the middle and semi circular at the ends. find the perimeter of capsule of its length is 30mm and diameter of semi -circular ends is 10mm​

Answer 1

Answer:

Given: 

Length of Capsule (l) = 14 mm

Diameter of Capsule = Diameter of Cylinder =5 mm

Radius = 2Diameter

Therefore, Radius of each Hemisphere = Radius of Cylinder = r = 25 = 2.5 mm

Length of Cylinder = AB = Total length of Capsule - Radius of left Hemisphere - Radius of Right Hemisphere 

                            =14−2.5−2.5=9 mm

Surface Area of Capsule = Curved Surface Area of Cylinder + Surface Area of Left Hemisphere + Surface Area of Right Hemisphere

                                      =2πrl+2πr2+2πr2

                                      =2πrl+4πr2

                                     =2×722×2.5×9+4×722×2.52

                                     =722[45+25]=722×70=220 mm2



Given: 

Length of Capsule (l) = 14 mm

Diameter of Capsule = Diameter of Cylinder =5 mm

Radius = 2Diameter

Therefore, Radius of each Hemisphere = Radius of Cylinder = r = 25 = 2.5 mm

Length of Cylinder = AB = Total length of Capsule - Radius of left Hemisphere - Radius of Right Hemisphere 

                            =14−2.5−2.5=9 mm

Surface Area of Capsule = Curved Surface Area of Cylinder + Surface Area of Left Hemisphere + Surface Area of Right Hemisphere

                                      =2πrl+2πr2+2πr2

                                      =2πrl+4πr2

                                     =2×722×2.5×9+4×722×2.52

                                     =722[45+25]=722×70=220 mm2

Step-by-step explanation:

please mark me as brainlist and give thanks

Answer 2

Answer:

Step-by-step explanation:

lenghth of rectangle=30mm

breadth of rectangle=10mm

radius of semi circle=5mm

WKT,

the perimeter of rectangle =2(l+b)

BUT IN THIS QUESTION IF WE WILL TAKE THE BREADTH OF THE RECTANGLE WHILE FINDING THE PERIMETER OF THE RECTANGLE AS WELL AS WHILE FINDING THE PERIMETER OF THE SEMI-CIRCLE,THEN THE ANSWER WILL BE WRONG.THEREFORE WE WILL TAKE IT ONLY ONCE AND THAT TOO WHILE FINDING THE PERIMETER OF SEMI-CIRCLE.

=2*l

=2*30

=60mm

WKT,

THE PERIMETER OF 1 SEMI-CIRCLE =2$\pi$r/2=$\pi$r

THEREFORE PERIMETER OF 2 SEMI-CIRCLES=2*$\pi$r

=2$\pi$r

=2*22/7*5

=220/7

=31.42mm

THEREFORE THE PERIMETER OF THE WHOLE CAPSULE

=PERIMETER OF RECTANGLE+PERIMETER OF 2 SEMI-CIRLCES

=60mm+31.42mm

=91.42mm

HOPE IT HELPS YOU MATE!

PLZ MARK ME AS BRAINLIEST AS IT TOOK ME A LOT OF TIME AS WELL AS EFFORT TO GIVE YOUR ANSWER.

HOPW YOU UNDERSTAND MATE.