Question

the shape of a flower basket is hemisphere with radius 60 cm and upper shape of conical with height 120 cm from the bottom surface then find the CSA of hhemisphere. and also find that ifif the cost of painting the glass outside is rupees 1.20 per metre square then find the total cost of painting the sea CSAof the glass

Answer 1

Answer:

2.2608m² and it will cost 2.71296rupees.

Step-by-step explanation:

the busket's radius is-60cm

and the height is- 120cm

then the CSA will be= πrl cm²

= 22/7×60×120cm²

= 22608cm² or 2.2608m²

to paint the total CSA it will cost-(1.20×2.2608)rupees

=2.71296 rupees.

Answer 2

The CSA of the hemisphere is 2.2 m² and the cost of painting is 3.96 rupees.

Given,

The radius of the hemisphere = 60 cm

Height of the cone =  120-60 = 60 cm

To Find,

The CSA of the hemisphere and the cost of painting the glass at 1.2 Rs per meter square.

Solution,

The formula for calculating the CSA of the hemisphere is

CSA of hemisphere = 2πr² = 2*22/7*60*60

CSA of hemisphere = 22628.5 cm² = 2.22628 m² ≈ 2.2 m²

Now,

The CSA if cone will be

CSA of cone = πrl = 22/7×60×60

CSA of cone = 11314.2 cm² = 1.13142 m² ≈ 1.1 m²

The total area that need to be painted = 2.2+1.1 = 3.3 m²

The cost of painting the CSA of the glass = 3.3*1.2 = 3.96 rupees.

Hence, the CSA of the hemisphere is 2.2 m² and the cost of painting is 3.96 rupees.