Math, asked by krsndp, 5 months ago

The shape of a garden is, as shown in the adjoining
figure, semicircular at the ends and rectangular in the
middle. Find the area and perimeter of the garden.
140 m
[Hint: Length of rectangle = 250 - 2r.]​

Answers

Answered by ranjansingh2571982
1

Answer:

Ncert solutions

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Mathematics

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Chapters in NCERT Solutions - Mathematics , Class 8

Exercises in Mensuration

Question 6

The shape of a garden is rectangular in the middle and semi-circular at the ends as

shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is

20 – (3.5 + 3.5 meters]

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Solution::

Given: Total length = 20 m

Diameter of semi circle = 7 m

Radius of semi circle = 7/2 = 3.5 m

Length of rectangular field

= 20 - (3.5 + 3.5) = 20 - 7 = 13 m

Breadth of the rectangular field = 7 m

Area of rectangular field = l x b

= 13 x 7 = 91m^2m

2

Area of two semi circles = 2 1/2 π * r^2

= 2 1/2 22/7 3.5 3.5

= 38.5 m2

Area of garden = 91 + 38.5 = 129.5 m2

Now Perimeter of two semi circles = 2 π r = 2 22/7 3.5 = 22 m

And Perimeter of garden = 22 + 13 + 13

= 48 m.

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