Question

the shape of a garden is rectangular in the middle and semicircle at the ends as shown in the diagram. find the area and the perimeter of this garden (length of rectangle is 20-(3.5+3.5)metres)​

Answer 1

Answer:

20 m = Total length.

7 m = Diameter.

7 / 2 = 3.5 m = Radius.

= 20 - ( 3.5 + 3.5 ) = 20 - 7 = 13 m

= 7 m = Breadth.

Length × Breadth = area of rectangular field.

= 13 × 7 = 91 cm²

Answer 2

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Total area of the garden = Area of the rectangular portion + The sum of the areas of the pair of semi-circles

$l.b + 2 \times \frac{1}{2}\pi {r}^{2}$

$= (13 \times 7) {m}^{2} +$

$(2 \times \frac{1}{2} \times \frac{22}{7} \times 3.5 \times 3.5) {m}^{2}$

$= (91 + 38.5) {m}^{2} = 129.5 {m}^{2}$

Perimeter of the garden =2× length of rectangular portion + circumference of the circle

$= (2 \times 13 + 2 \times \frac{22}{7} \times 3.5)m$

$= (26 + 22)m = 48m$