Question

the shape of a garden is rectangular in the middle and semicircular
at the ends as shown in the diagram Find the area and the perimeter
T of this garden (Length of rectangle is
7m 20-3.5+3.5) metres)​

Answer 1

Hope it helps you........................

Answer 2

Question ::-

The shape of a garden is rectangular in the middle and semicircular at the ends as shown in the diagram. Find the area and the perimeter of this garden. [Length of rectangle is 20 – (3.5 + 3.5) metres]

Given ::-

• The shape of a garden is rectangular in the middle and semicircular at the ends

• Length of rectangle = 20 – (3.5 + 3.5)m

To find ::-

• Find the area of park ?

• Find the perimeter of park ?

Solution ::-

• Length of rectangle = 20 – (3.5 + 3.5)

= 20 - 7

= 13 m

______

Area of rectangle

= length × breadth

= 13 × 7

= 91 ${m}^{2}$

_______

Area of two circular ends

= 2 ( $\dfrac{1}{2}π{r}^{2}$)

= $π{r}^{2}$

= $\dfrac{22}{7}×{7}{2}×{7}{2}$

= $\dfrac{77}{2}$

= 38.5 ${m}^{2}$

________

Total area

= Area of the rectangle + Area of two ends

= 91 ${m}^{2}$ + 38.5 ${m}^{2}$

= 129.5 ${m}^{2}$

______

Total perimeter

= Perimeter of the rectangle + Perimeter of two ends

= 2 (l + b) + 2 × (πr) – 2(2r)

= 2 (13 + 7) + 2($\dfrac{22}{7}$ × $\dfrac{7}{2}$) – 4 × $\dfrac{7}{2}$

= 2 × 20 + 22 – 14

= 40 + 22 – 14

= 48 m