Question

the shape of a garden is rectangular in the middle and semicircular at the ends shown in the diagram in the . find the area and the perimeter of this garden length of rectangle is 20- 3.5+3.5 meters
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Answer 1

Solution 3:

We know that,

length of the garden=20 m

diameter of semicircle=7m,r=3.5m

(breadth of the rectangle)

Length of rectangle=20m-3.5m-3.5m20m−3.5m−3.5m

=13 m

Area of rectangle=length\times breadthlength×breadth

=13m\times7m=13m×7m

=91\ m^2=91 m2

Area of semi-circle =\frac{1\ }{2}\times\pi\times\left(3.5\right)^221 ×π×(3.5)2

==\frac{1}{2}\times\frac{22}{7}\times\frac{35}{10\ }\times\frac{35}{10}=21×722×10 35×1035

=19.25\ m^2=19.25 m2

Area of garden=91+19.25+19.2591+19.25+19.25

=129.5\ m^2=129.5 m2

Perimeter of garden=perimeter of rectangle+2(Perimeter of semicircle)

Perimeter of rectangle==2\times length=2×length

=2\times26=2×26

=26\ m=26 m

Perimeter of semicircle==\pi r=πr

=\frac{22}{7}\times3.5=722×3.5

=\frac{22}{7}\times\frac{35}{10}=722×1035

=11m

Perimeter of Garden=26m+11m+11

=48m