Question

the shape of a garden is rectangular in the middle and semicircular at the end of a shown in figure find the area and the perimeter of this Garden

Answer 1

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Length of rectangular garden = 13 m..... (given)

Radius of the semicircular end = 3.5 m

Now,

We know that 2 Semicircles = 1 circle.

Therefore,

Perimeter of the garden = 2 × length of rectangle + circumference of circle.




=> 2 × 13 + 2 × 22/7 × 3.5

=> 26 + 22

=> 48 m ......... (ANS)

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Answer 2

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Total area of the garden = Area of the rectangular portion + The sum of the areas of the pair of semi-circles

$l.b + 2 \times \frac{1}{2}\pi {r}^{2}$

$= (13 \times 7) {m}^{2} +$

$(2 \times \frac{1}{2} \times \frac{22}{7} \times 3.5 \times 3.5) {m}^{2}$

$= (91 + 38.5) {m}^{2} = 129.5 {m}^{2}$

Perimeter of the garden =2× length of rectangular portion + circumference of the circle

$= (2 \times 13 + 2 \times \frac{22}{7} \times 3.5)m$

$= (26 + 22)m = 48m$