Math, asked by hassanrehan36884, 7 months ago

The shape of a garden is rectangular in the middle and semi circular
at the ends as shown in the diagram. Find the area and the perimeter
T
of this garden [Length of rectangle is
7m 20-(3.5 +3.5) metres).
1
1
20 m​

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Answers

Answered by jaiswalsameeksha2005
2

Answer:

perimeter = 62

area=178.5

Step-by-step explanation:

primeter=2πr+40 (2 sides of rectangle)

= 2*22/7*7/2+40

=22+40=62m

area=πr²+(length *breadth)

= 22/7*7/2*7/2 +( 20*7)

=77/2+140

= 178.5m²

Answered by mehreennaikoo123
1

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Total area of the garden = Area of the rectangular portion + The sum of the areas of the pair of semi-circles

l.b + 2 \times  \frac{1}{2}\pi {r}^{2}

 = (13 \times 7) {m}^{2}  +

(2 \times  \frac{1}{2}  \times  \frac{22}{7}  \times 3.5 \times 3.5) {m}^{2}

 = (91 + 38.5) {m}^{2}  = 129.5 {m}^{2}

Perimeter of the garden =2× length of rectangular portion + circumference of the circle

 = (2 \times 13 + 2 \times  \frac{22}{7}  \times 3.5)m

 = (26 + 22)m = 48m

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