Question

The shape of a garden is rectangular in the middle and semi circlar at the ends as shown in the diagram.find the area and the perimeter of this garden {length of rectangle is 20-(3.5+3.5)metres]​

Answer 1

Answer:

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Answer 2

Question :-

The shape of a garden is rectangular in the middle and semi circlar at the ends as shown in the diagram.find the area and the perimeter of this garden {length of rectangle is 20-(3.5+3.5)metres]

Given :-

• Length of rectangle = 20-(3.5+3.5)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 20 - 7

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 13m

To find :-

• Area of garden ?

• Perimeter of garden ?

Solution :-

Length of rectangle = 13m

Area of the rectangle = l × b

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 13 × 7

$⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 91 {m}^{2}$

Area of two circular ends

$= 2( \dfrac{1}{2}\pi {r}^{2})$

$= \pi {r}^{2}$

$= \dfrac{22}{7} \times \dfrac{7}{2} \times \dfrac{7}{2}$

$= \dfrac{77}{2} {m}^{2}$

$= 38.5 {m}^{2}$

_____________

Total area

= Area of the rectangle + Area of two ends

$= 91 {m}^{2} + 38.5 {m}^{2}$

$= 129.5 {m}^{2}$

Total perimeter

= Perimeter of the rectangle + Perimeter of two ends

$= 2(l + b) + 2 \times (\pi \: r) - 2(2r)$

$= 2(13 + 7) + 2( \dfrac{22}{7} \times \dfrac{7}{2}) - 4 \times \dfrac{7}{2}$

$= 2 \times 20 + 22 - 14$

$= 40 + 22 - 14$

$= 48m$