The shape of a garden is rectangular in the middle and semi circular at the ends.find the area and the perimeter of this garden
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Area of garden = l×b+πb²/4
Perimeter of garden = 2l + πb
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for the rectangular at the middle
the area = l * b
the area of semi circle on the length side = 1/2 * 22/7 * (l/2)^ 2
the area of semi circle on breadth side = 1/2 * 22/7 * (b/2)^ 2
therefore ,
area = l * b + 1/2 * 22/7 * (l/2)^ 2 + 1/2 * 22/7 * (b/2)^ 2
the perimeter of rectangle = 2(l+b)
the circumferemce of semi circle on the length side = 1/2 * 22/7 * l/2
the circumference of semi circle on breadth side = 1/2 * 22/7 * b/2
therefore ,
perimeter = 2(l+b) + + 1/2 * 22/7 * l/2 + 1/2 * 22/7 * b/2
the area = l * b
the area of semi circle on the length side = 1/2 * 22/7 * (l/2)^ 2
the area of semi circle on breadth side = 1/2 * 22/7 * (b/2)^ 2
therefore ,
area = l * b + 1/2 * 22/7 * (l/2)^ 2 + 1/2 * 22/7 * (b/2)^ 2
the perimeter of rectangle = 2(l+b)
the circumferemce of semi circle on the length side = 1/2 * 22/7 * l/2
the circumference of semi circle on breadth side = 1/2 * 22/7 * b/2
therefore ,
perimeter = 2(l+b) + + 1/2 * 22/7 * l/2 + 1/2 * 22/7 * b/2
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