the shape of a garden is rectangular in the middle and semi circle at the end as shown in the diagram . find the area and the perimeter of this garden [length of rectangle is 20-(3.5+3.5) meters.
Answers
Answer:
Step-by-step explanation:
Solution::
Given: Total length = 20 m
Diameter of semi circle = 7 m
Radius of semi circle = 7/2 = 3.5 m
Length of rectangular field
= 20 - (3.5 + 3.5) = 20 - 7 = 13 m
Breadth of the rectangular field = 7 m
Area of rectangular field = l x b
= 13 x 7 = 91m^2
Area of two semi circles = 2 1/2 π * r^2
= 2 1/2 22/7 3.5 3.5
= 38.5 m2
Area of garden = 91 + 38.5 = 129.5 m2
Now Perimeter of two semi circles = 2 π r = 2 22/7 3.5 = 22 m
And Perimeter of garden = 22 + 13 + 13
= 48 m.
Answer:
Given Total length = 20 m Diameter of semi circle = 7m
∴
Radius of semi circle =
7
2
=
3.5
m
Length of rectangular field = 20 - (3.5+3.5) = 20 - 7 = 13 m
Breadth of the rectangular field = 7m
Area of garden = Area of rectangular field + Area of the two semi-circular ends.
∴
Area of rectangular field =
l
×
b
=
13
×
7
=
91
m
2
Area of two semi circles =
2
×
1
2
π
r
2
=
2
×
1
2
×
22
7
×
3.5
×
3.5
=
38.5
m
2
Area of garden =
91
+
38.5
=
129.5
m
2
Perimeter of garden =
2
×
length of the rectangular field +
2
×
length of the semi-circular arcs.
Now Perimeter of two semi cricles =
2
×
π
r
=
2
×
22
7
×
3.5
=
22
m
And Perimeter of garden = 22 + 13 + 13 = 48 m